2x-[4-2(x-1)]=10

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Solution for 2x-[4-2(x-1)]=10 equation:


Simplifying
2x + -1[4 + -2(x + -1)] = 10

Reorder the terms:
2x + -1[4 + -2(-1 + x)] = 10
2x + -1[4 + (-1 * -2 + x * -2)] = 10
2x + -1[4 + (2 + -2x)] = 10

Combine like terms: 4 + 2 = 6
2x + -1[6 + -2x] = 10
2x + [6 * -1 + -2x * -1] = 10
2x + [-6 + 2x] = 10

Reorder the terms:
-6 + 2x + 2x = 10

Combine like terms: 2x + 2x = 4x
-6 + 4x = 10

Solving
-6 + 4x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 4x = 10 + 6

Combine like terms: -6 + 6 = 0
0 + 4x = 10 + 6
4x = 10 + 6

Combine like terms: 10 + 6 = 16
4x = 16

Divide each side by '4'.
x = 4

Simplifying
x = 4

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